## Part 4 Aptitude Shortcuts given by (ibps whatsapp group members)

Part 4

Covered all the aptitude questions of whatsapp group from

15-04-2016; 10:00 PM
to
26-04-201612:15 AM

The busiest whatsapp group for IBPS/SSC CGL preparation.Here we go with the aptitude stuff that was covered in whatsapp (for ibps po / ssc cgl ) with all the shortcuts required to solve difficult model aptitude questions.I will try to upload all the questions discussed.

## <<<< >>>>

1) A cloth merchant said that due to to slump in the market he sells the cloth at 10% loss but he uses a false meter scale and actually gains 15%. Find the actual length of the scale? (Unknown Gal)

Ans:
By Vikas Awasthi

100% of cloth ----90
? % of cloth -----115

?=115*100/90=127.78%

127.78=1000
100=782.6

==========================

2)A person took a loan of Rs. 6000 for 3 years, at 5% per annum compound interest. He repaid Rs. 2100 in each of the first 2 years. The amount he should pay at the end of 3rd year to clear all his debts is

Ans:

6000▶105%▶6300
6300-2100=4200

4200▶105%▶4410
4410-2100=2310

2310▶105%▶2425.5

============================

3)A person deposit a sum Rs.12000 in a Bank @ roi 8% pr Annum, interest would be compounded. How long it will take to get interest same as the sum invested....?

Shortcut :

RT=72

If amount dbl by CI

R=8

T=9

This is called rule no 72 in CAT

wat is rule 72??

It means if Amount double by CI

RT=72 should be true

============================
4) One man and six women working together can do a job in 10 days. The same job is done by two men in ‘p’ days and by eight women in p+5 days. By what percentage is the efficiency of a man

greater than that of a woman?

Solution:

m:20; w:120

% =>100/20 x 100=500%

=============================

5)A man travels 35KM partly at 4kmph and partly at 5kmph. If he covers the former distance @ 5khe time taken to cover the whole distance at the original rate is (in hours)?

Solution:

4kmph*5h+ 5kmph*3h= 35

5kmph*5h+ 4kmph*3h= 37

=============================

6)With given rate of Simple Int, the ratio of principle and amount for certain period of time is 4:5 . After 3 years , with the same rate of interest the ratio of the principle and amount becomes 5:7. The rate of interest per annum is ?

Shortcut:

4 :5  25% increase

5:7 40% increase.

15% in 3 years

5% in 1 year.

==============================================

7) A man walks frm his house to ralway statn. If he walks at 5kmph, he mises a train by 7min. If he walks at 6kmph, he reachs statn 5min befr. Fnd dstnc cvrd by him to reach statn.

Solution:

here speed ratio = 5:6

time ratio= 6:5
->>> 1 gap(6-5) time difference is 12min
so for 1 gap
-->> time = 12min
for 6
->>>6*12=72min

or

we can say for 5
-->> 5*12=60

distance = 72*5/60
=6km

------------OR---------------

--->> 60*6/60 =6km

------------OR---------------

alternatively let time = t min so 5(t+7)=6(t-5) t= 65min

distance= 5(65+7)/60 = 6km

---------------------OR---------------------

5*6/1 * 12/60 = 6km

============================

8)Speed of A and B are in ratio 3:4. A takes 20 min more than B to reach distance . In what time A reach?

Solution :

4-3=1 part

1 part 20

4 part 80

------------OR--------------

speed ratio = 3:4 time ratio = 4:3
original time =4*20=80min

Or Sol-2
alternatively let b take t min 3/4 = t/(t+20) t=60 min

a will take 80min

===========================
9)A is twic as fast as B and B is thric as C. The journey cvrd by C in 42min wil b cvrd by A in?

Shortcut :

a=2b b=3c ->> a=6c

a and c speed ratio = 6:1 sp their time ratio = 1:6 1/6 = t/42

t= 7min

=========================
10)A car covers a distance of 715 km at constant speed. if speed was 10kmph more, than it would havw taken 2hr less to cover. find original speed?

Solution :

let speed= xkmph
715/x - 715/(x+10) = 2

x = 55kmph

==============================

11)A takes 2 hour more than B to walk d km.if A doubles his speed, he can make it in 1 hour less than B.how much tym duz b take for walking d km?

Solution :

let A take t+2 hours then B take t hrs speed A=s
A double speed sA=2s

now distance = s(t+2)= 2s(t-1) t= 2hrs

===============================

12) Two trains start from station A and B and travel towards each other at 50 kmph and 60 kmph. At time of their meeting, the 2nd train travelled 120 km more than 1st. Distnce between A and B is?

Solution :

let they meet after t time so d/50 = (d+120)/60

d=600km

total distance = d+ d+120 = 1320

===========================

13)By hw mch % must a motrist increase his spd in ordr to reduc the tim by 20% to cvr certan dstnc?

Shortcut :

let he has to travel a distance of 100km 100--> 80 80--> 100

%increase in speed = 20*100/80 = 25%

-------------OR------------

reduced=1/5

So incrs should be=1/(5-1)=1/4=25%

==============================
14)A fast tran taks 3hr les than slow tran fr a journey f 600km. If spd f slw tran is 10kmph les than fast tran. Fnd their spds

Solution :
let the speed of fast train is x kmph and slow train = x-10 kmph 600/(x-10) - 600/x = 3
x= 50kmph

so their speeds are 50kmph and 40 kmph

==========================

15)Two taps can fill a tank in 20 min and 30 min
respectively.There is an outlet tap at exactly half level of that rectangular tank which can pump out 50 litres of water per minute.If the outlet is open , then it takes 24 minutes to fill an empty tank. What is the volume of the tank?

Shortcuts :

20       3
60
30       2

30/5 = 6
Half tank fill in 6 minutes
So hole is active for 18 minutes

18*50 = 900 full tank

-------------OR------------

6 min for filling half tank after hole
18 min with hole.
1/6 - 1/18 = 1/9
9*50 = 450 half

900 full

-----------------OR--------------

A + B = 1/20 + 1/30 = 12 min

Half tank = 6 min

To fill other half it takes 24 - 6 = 18 min

1/6 - 1/x = 1/18

x = 9

9*50 = 450 for half tank

900 for full tank

---------------OR-----------------

Half tank is full in 6 minutes

Then for 18 minutes both tap and hole is active

Tap will fill 1.5 th of tank in 18

Rest of half + 1 full tank (that is eventually emptied by hole in 18 minutes)

Tank = 18*50 = 900

============================

16)Two tran strt frm statn A and B and travl twrds ech othr at 50kmph and 60kmph. At tim f their metng, the 2nd tran travld 120km mr than 1st. Distnc btwn A and B is?

Solution :

(50+60) * 120/(60-50)

110* 12=  1320 km

===========================

17)A taxi service charges ₹5.50 for the first 1/5th of a mile, ₹1.50 for each additional 1/5th of a mile, and 20 cents perminute of waiting time. Joan took a cab from her place to a flower shop 8 miles away, where she bought a bouquet, then another 3.6 miles to her mother's place. The driver had to wait 9 minutes while she bought the bouquet. What was the fare?

Solution :

For 1st 1/5   5.5
For rest 4/5  1.5*4= 6

So frst mile costs
6+5.5 = 11.5

Total distance 11.6 miles
Frst mile calculated
Rest is 10.6
Normal 1 mile costs
7.5
For 10.6 = 79.5
Total 79.5+11.5= 91 Rs.

Now waiting charge
20*9 = 180 Cents

91 Rs  + 180 cents

--------------OR---------------

7.5*(8+3.6) + 4 + 1.8 = 92.8

-------------OR--------------

5.5  + (7.8 + 3.6)*1.5 *5  = 91 +180 cents

===========================

18) A train overtakes two persons who are walking in the same direction in which the train is going , @ 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is ?

Solution  :

2*5/18  = x/9 -  x/10

X= 50

## <<<< >>>>

Updated till

12:40 AM ; 27-04-2016

## <<<< >>>>

<<<<<< Rest will be updated >>>>>>